What is the answer to log_{10}(36)+log_{10}(x)=34 ?

The answer to log_{10}(36)+log_{10}(x)=34 is x=(5^{34}*2^{32})/9

Solve for x: log_{10}(36)+log_{10}(x)=34

The solution is x=(5^{34}*2^{32})/9

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lo g_{10} (36) + lo g_{10} (x) = 34

x = \frac{5 ^{34} \cdot 2 ^{32}}{9}

Decimal Notation

x = 2.77778 E 32

Solution steps

lo g_{10} (36) + lo g_{10} (x) = 34

Move

lo g_{10} (36)

to the right side

lo g_{10} (x) = 34 - lo g_{10} (36)

Apply log rules

x = \frac{5 ^{34} \cdot 2 ^{32}}{9}

Verify Solutions:

x = \frac{5 ^{34} \cdot 2 ^{32}}{9}

True

The solution is

x = \frac{5 ^{34} \cdot 2 ^{32}}{9}

ln (x) + ln (x - 8) = 5

lo g_{10} (\frac{1}{1 - x}) = 2

lo g_{\frac{1}{2}} (2 x - 3) = 1

\frac{1}{2} ln (x) = ln (2 x - 1)

e^{- 2 l n (x)} = x^{- 2}

What is the answer to log_{10}(36)+log_{10}(x)=34 ?
The answer to log_{10}(36)+log_{10}(x)=34 is x=(5^{34}*2^{32})/9
Solve for x: log_{10}(36)+log_{10}(x)=34
The solution is x=(5^{34}*2^{32})/9