What is the answer to 2log_{10}(x+6)=log_{10}(x+7) ?

The answer to 2log_{10}(x+6)=log_{10}(x+7) is x=(-11+sqrt(5))/2

Solve for x: 2log_{10}(x+6)=log_{10}(x+7)

The solution is x=(-11+sqrt(5))/2

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2 lo g_{10} (x + 6) = lo g_{10} (x + 7)

x = \frac{- 11 + 5}{2}

Decimal Notation

x = - 4.38196 \dots

Solution steps

2 lo g_{10} (x + 6) = lo g_{10} (x + 7)

Apply log rules

(x + 6)^{2} = x + 7

Solve

(x + 6)^{2} = x + 7 : x = \frac{- 11 + 5}{2}, x = \frac{- 11 - 5}{2}

x = \frac{- 11 + 5}{2}, x = \frac{- 11 - 5}{2}

Verify Solutions:

x = \frac{- 11 + 5}{2}

True

, x = \frac{- 11 - 5}{2}

False

The solution is

x = \frac{- 11 + 5}{2}

lo g_{10} (x - 1) = - 1

lo g_{10} (x) = 7.2

lo g_{2 x - 1} (3 x^{2} + 6) = 2

0 = ln (x - 1) + 2

0 = ln (x - 1) - 2

What is the answer to 2log_{10}(x+6)=log_{10}(x+7) ?
The answer to 2log_{10}(x+6)=log_{10}(x+7) is x=(-11+sqrt(5))/2
Solve for x: 2log_{10}(x+6)=log_{10}(x+7)
The solution is x=(-11+sqrt(5))/2