What is the answer to x+log_{10}(x+4)=6 ?

The answer to x+log_{10}(x+4)=6 is x=(\W_{0}(ln(10)*10^{10}))/(ln(10))-4

Solve for x: x+log_{10}(x+4)=6

The solution is x=(\W_{0}(ln(10)*10^{10}))/(ln(10))-4

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x + lo g_{10} (x + 4) = 6

x = \frac{W _{0} ( ln ( 10 ) \cdot 1 0 ^{10} )}{ln ( 10 )} - 4

Decimal Notation

x = 5.04365 \dots

Solution steps

x + lo g_{10} (x + 4) = 6

Move

x

to the right side

lo g_{10} (x + 4) = 6 - x

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

1 0^{l o g_{10} (x + 4)} = 1 0^{6 - x}

Simplify

1 0^{l o g_{10} (x + 4)} : x + 4

x + 4 = 1 0^{6 - x}

Solve

x + 4 = 1 0^{6 - x} : x = \frac{W _{0} ( ln ( 10 ) \cdot 1 0 ^{10} )}{ln ( 10 )} - 4

x = \frac{W _{0} ( ln ( 10 ) \cdot 1 0 ^{10} )}{ln ( 10 )} - 4

Verify Solutions:

x = \frac{W _{0} ( ln ( 10 ) \cdot 1 0 ^{10} )}{ln ( 10 )} - 4

True

The solution is

x = \frac{W _{0} ( ln ( 10 ) \cdot 1 0 ^{10} )}{ln ( 10 )} - 4

lo g_{2} (9 x + 12) - lo g_{2} (3) = 4

3 = lo g_{10} (p (x)) (24 x - 18 x^{2})

ln (x - 2) = 0.5

lo g_{4} (x + 5) + lo g_{4} (3 x - 7) = 2

lo g_{3} (2 x + 3) = 2

What is the answer to x+log_{10}(x+4)=6 ?
The answer to x+log_{10}(x+4)=6 is x=(\W_{0}(ln(10)*10^{10}))/(ln(10))-4
Solve for x: x+log_{10}(x+4)=6
The solution is x=(\W_{0}(ln(10)*10^{10}))/(ln(10))-4