What is the answer to log_{6}(3-m)+log_{6}(-m-2)=2 ?

The answer to log_{6}(3-m)+log_{6}(-m-2)=2 is m=-6

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log_{6}(3-m)+log_{6}(-m-2)=2

lo g_{6} (3 - m) + lo g_{6} (- m - 2) = 2

m = - 6

Solution steps

lo g_{6} (3 - m) + lo g_{6} (- m - 2) = 2

Apply log rules

(3 - m) (- m - 2) = 36

Solve

(3 - m) (- m - 2) = 36 : m = 7, m = - 6

m = 7, m = - 6

Verify Solutions:

m = 7

False

, m = - 6

True

The solution is

m = - 6

lo g_{6} (3 x) = 2

lo g_{10} (z) = 2

2 lo g_{5} (x) = 3 - lo g_{x} (5)

x, y^{5} = ln (x y)

200 = 93 lo g_{10} (d) + 65

What is the answer to log_{6}(3-m)+log_{6}(-m-2)=2 ?
The answer to log_{6}(3-m)+log_{6}(-m-2)=2 is m=-6
Solve for m: log_{6}(3-m)+log_{6}(-m-2)=2
The solution is m=-6