What is the answer to (ln(2x))/(ln(4x))=4 ?

The answer to (ln(2x))/(ln(4x))=4 is x= 1/(e^{\frac{7ln(2)){3}}}

Solve for x: (ln(2x))/(ln(4x))=4

The solution is x= 1/(e^{\frac{7ln(2)){3}}}

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\frac{ln ( 2 x )}{ln ( 4 x )} = 4

x = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

Decimal Notation

x = 0.19842 \dots

Solution steps

\frac{ln ( 2 x )}{ln ( 4 x )} = 4

Multiply both sides by

ln (4 x)

\frac{ln ( 2 x )}{ln ( 4 x )} ln (4 x) = 4 ln (4 x)

Simplify

ln (2 x) = 4 ln (4 x)

Apply log rules

x = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

Verify Solutions:

x = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

True

The solution is

x = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

lo g_{x} (4) = \frac{- 1}{2}

62 = 10 lo g_{10} (\frac{85}{x})

lo g_{3} (x + 5) = lo g_{3} (15 - x)

ln (x + 2) = x

x, - lo g_{10} (x) = 6.63

What is the answer to (ln(2x))/(ln(4x))=4 ?
The answer to (ln(2x))/(ln(4x))=4 is x= 1/(e^{\frac{7ln(2)){3}}}
Solve for x: (ln(2x))/(ln(4x))=4
The solution is x= 1/(e^{\frac{7ln(2)){3}}}