What is the answer to log_{3}(2m-5)=1+log_{3}(m+2) ?

The answer to log_{3}(2m-5)=1+log_{3}(m+2) is No Solution for m\in\mathbb{R}

Solve for m: log_{3}(2m-5)=1+log_{3}(m+2)

The solution is No Solution for m\in\mathbb{R}

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lo g_{3} (2 m - 5) = 1 + lo g_{3} (m + 2)

No Solution for m \in R

Solution steps

lo g_{3} (2 m - 5) = 1 + lo g_{3} (m + 2)

Apply log rules

2 m - 5 = 3 (m + 2)

Solve

2 m - 5 = 3 (m + 2) : m = - 11

m = - 11

Verify Solutions:

m = - 11

False

The solution is

No Solution for m \in R

lo g_{10} (- 7 x) = 3

ln (6 - x) = 0.6

lo g_{3} (x) = lo g_{2} (3)

lo g_{6} (8) = 3 lo g_{6} (x)

ln (x^{2.5}) - 0.5 ln (x) = ln (25)

What is the answer to log_{3}(2m-5)=1+log_{3}(m+2) ?
The answer to log_{3}(2m-5)=1+log_{3}(m+2) is No Solution for m\in\mathbb{R}
Solve for m: log_{3}(2m-5)=1+log_{3}(m+2)
The solution is No Solution for m\in\mathbb{R}