What is the answer to log_{4}(x^2-17)=2 ?

The answer to log_{4}(x^2-17)=2 is x=sqrt(33),x=-sqrt(33)

Solve for x: log_{4}(x^2-17)=2

The solution is x=sqrt(33),x=-sqrt(33)

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lo g_{4} (x^{2} - 17) = 2

x = 33, x = - 33

Decimal Notation

x = 5.74456 \dots, x = - 5.74456 \dots

Solution steps

lo g_{4} (x^{2} - 17) = 2

Apply log rules

x^{2} - 17 = 16

Solve

x^{2} - 17 = 16 : x = 33, x = - 33

x = 33, x = - 33

2 lo g_{9} (5) = lo g_{9} (x)

lo g_{x} (8) = - \frac{3}{4}

lo g_{x} (196) = 2

lo g_{4} (2 x) + 3 lo g_{4} (7) = 3

\frac{2}{x ln ( x )} = 0

What is the answer to log_{4}(x^2-17)=2 ?
The answer to log_{4}(x^2-17)=2 is x=sqrt(33),x=-sqrt(33)
Solve for x: log_{4}(x^2-17)=2
The solution is x=sqrt(33),x=-sqrt(33)