What is the answer to log_{3}(7-4x)-log_{3}(x-5)=2 ?

The answer to log_{3}(7-4x)-log_{3}(x-5)=2 is No Solution for x\in\mathbb{R}

Solve for x: log_{3}(7-4x)-log_{3}(x-5)=2

The solution is No Solution for x\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

lo g_{3} (7 - 4 x) - lo g_{3} (x - 5) = 2

No Solution for x \in R

Solution steps

lo g_{3} (7 - 4 x) - lo g_{3} (x - 5) = 2

Add

lo g_{3} (x - 5)

to both sides

lo g_{3} (7 - 4 x) - lo g_{3} (x - 5) + lo g_{3} (x - 5) = 2 + lo g_{3} (x - 5)

Simplify

lo g_{3} (7 - 4 x) = 2 + lo g_{3} (x - 5)

Apply log rules

7 - 4 x = 9 (x - 5)

Solve

7 - 4 x = 9 (x - 5) : x = 4

x = 4

Verify Solutions:

x = 4

False

The solution is

No Solution for x \in R

3 x lo g_{10} (x) = 9

0.5 = - lo g_{10} (x)

ln (x) + ln (x + 4) = ln (15) + ln (3)

lo g_{10} (x) = 207

lo g_{10} (x) = 232

What is the answer to log_{3}(7-4x)-log_{3}(x-5)=2 ?
The answer to log_{3}(7-4x)-log_{3}(x-5)=2 is No Solution for x\in\mathbb{R}
Solve for x: log_{3}(7-4x)-log_{3}(x-5)=2
The solution is No Solution for x\in\mathbb{R}