What is the answer to log_{10}(x^2)=2.0279 ?

The answer to log_{10}(x^2)=2.0279 is x=sqrt(10^{2.0279)},x=-sqrt(10^{2.0279)}

Solve for x: log_{10}(x^2)=2.0279

The solution is x=sqrt(10^{2.0279)},x=-sqrt(10^{2.0279)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

lo g_{10} (x^{2}) = 2.0279

x = 1 0^{2.0279}, x = - 1 0^{2.0279}

Decimal Notation

x = 10.32642 \dots, x = - 10.32642 \dots

Solution steps

lo g_{10} (x^{2}) = 2.0279

Apply log rules

x^{2} = 1 0^{2.0279}

Solve

x^{2} = 1 0^{2.0279} : x = 1 0^{2.0279}, x = - 1 0^{2.0279}

x = 1 0^{2.0279}, x = - 1 0^{2.0279}

0 = 1 - ln (x)

x = - ln (2 - x)

a, 1 = b lo g_{5} (6 + a)

ln (3 x + 4) = 6

ln (2 x + 1) + ln (x + 2) = 0

What is the answer to log_{10}(x^2)=2.0279 ?
The answer to log_{10}(x^2)=2.0279 is x=sqrt(10^{2.0279)},x=-sqrt(10^{2.0279)}
Solve for x: log_{10}(x^2)=2.0279
The solution is x=sqrt(10^{2.0279)},x=-sqrt(10^{2.0279)}