What is the answer to 2log_{2}(x)-log_{2}(5)=1 ?

The answer to 2log_{2}(x)-log_{2}(5)=1 is x=2^{(1+log_{2}(5))/2}

Solve for x: 2log_{2}(x)-log_{2}(5)=1

The solution is x=2^{(1+log_{2}(5))/2}

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2 lo g_{2} (x) - lo g_{2} (5) = 1

x = 2^{\frac{1 + l o g _{2} ( 5 )}{2}}

Decimal Notation

x = 3.16227 \dots

Solution steps

2 lo g_{2} (x) - lo g_{2} (5) = 1

Move

lo g_{2} (5)

to the right side

2 lo g_{2} (x) = 1 + lo g_{2} (5)

Divide both sides by

2

lo g_{2} (x) = \frac{1 + lo g _{2} ( 5 )}{2}

Apply log rules

x = 2^{\frac{1 + l o g _{2} ( 5 )}{2}}

Verify Solutions:

x = 2^{\frac{1 + l o g _{2} ( 5 )}{2}}

True

The solution is

x = 2^{\frac{1 + l o g _{2} ( 5 )}{2}}

ln (x) = 7.94

lo g_{3} (3 b) + lo g_{3} (b) = 2

lo g_{5} (8) - lo g_{5} (2 x) = 2

x, ln (x) = t + ln (4)

lo g_{10} (x) = lo g_{10} (4)

What is the answer to 2log_{2}(x)-log_{2}(5)=1 ?
The answer to 2log_{2}(x)-log_{2}(5)=1 is x=2^{(1+log_{2}(5))/2}
Solve for x: 2log_{2}(x)-log_{2}(5)=1
The solution is x=2^{(1+log_{2}(5))/2}