What is the answer to 1=3log_{10}(4x+10) ?

The answer to 1=3log_{10}(4x+10) is x=(\sqrt[3]{5}(1^2-(\sqrt[3]{10})^2))/(2^{5/3)}

Solve for x: 1=3log_{10}(4x+10)

The solution is x=(\sqrt[3]{5}(1^2-(\sqrt[3]{10})^2))/(2^{5/3)}

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1 = 3 lo g_{10} (4 x + 10)

Decimal Notation

x = - 1.96139 \dots

Solution steps

1 = 3 lo g_{10} (4 x + 10)

Switch sides

3 lo g_{10} (4 x + 10) = 1

Divide both sides by

3

lo g_{10} (4 x + 10) = \frac{1}{3}

Apply log rules

Solve

Verify Solutions:

True

The solution is

lo g_{6} (9 x) - 2 lo g_{6} (2) = 3

lo g_{7} (2 x - 3) = 2

lo g_{10} (x^{2} - x - 10) = 1

3 ln (4) + ln (x) = 3

ln (x) + ln (4) = ln (8)

What is the answer to 1=3log_{10}(4x+10) ?
The answer to 1=3log_{10}(4x+10) is x=(\sqrt[3]{5}(1^2-(\sqrt[3]{10})^2))/(2^{5/3)}
Solve for x: 1=3log_{10}(4x+10)
The solution is x=(\sqrt[3]{5}(1^2-(\sqrt[3]{10})^2))/(2^{5/3)}