What is the answer to log_{2}(x+1)=-3 ?

The answer to log_{2}(x+1)=-3 is x=-7/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2}(x+1)=-3

lo g_{2} (x + 1) = - 3

x = - \frac{7}{8}

Decimal Notation

x = - 0.875

Solution steps

lo g_{2} (x + 1) = - 3

Apply log rules

x + 1 = \frac{1}{8}

Solve

x + 1 = \frac{1}{8} : x = - \frac{7}{8}

x = - \frac{7}{8}

4 (lo g_{5} (x) + lo g_{x} (5)) = 10

x, y - 1 = ln (x)

ln (x) + ln (x^{2} + 1) = 8

lo g_{3} (x) = 1 - \frac{x}{2}

5 lo g_{5} (x) + 5 = 0