What is the answer to ln(3t+1)+ln(3t-1)=0 ?

The answer to ln(3t+1)+ln(3t-1)=0 is t=(sqrt(2))/3

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ln(3t+1)+ln(3t-1)=0

ln (3 t + 1) + ln (3 t - 1) = 0

t = \frac{2}{3}

Decimal Notation

t = 0.47140 \dots

Solution steps

ln (3 t + 1) + ln (3 t - 1) = 0

Apply log rules

(3 t + 1) (3 t - 1) = 1

Solve

(3 t + 1) (3 t - 1) = 1 : t = \frac{2}{3}, t = - \frac{2}{3}

t = \frac{2}{3}, t = - \frac{2}{3}

Verify Solutions:

t = \frac{2}{3}

True

, t = - \frac{2}{3}

False

The solution is

t = \frac{2}{3}

ln (5 x) = 1.7

ln (3 x - 12) = 8

ln (3) + ln (x - 3) = ln (x)

lo g_{2} (2 x^{3}) - 3 = 0.5

66 = 41 lo g_{10} (\frac{295}{x})

What is the answer to ln(3t+1)+ln(3t-1)=0 ?
The answer to ln(3t+1)+ln(3t-1)=0 is t=(sqrt(2))/3
Solve for t: ln(3t+1)+ln(3t-1)=0
The solution is t=(sqrt(2))/3