What is the answer to ln(t)=0.98ln(175)-0.52 ?

The answer to ln(t)=0.98ln(175)-0.52 is t=(175^{0.98})/(e^{0.52)}

Solve for t: ln(t)=0.98ln(175)-0.52

The solution is t=(175^{0.98})/(e^{0.52)}

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ln (t) = 0.98 ln (175) - 0.52

t = \frac{17 5 ^{0.98}}{e ^{0.52}}

Decimal Notation

t = 93.83052 \dots

Solution steps

ln (t) = 0.98 ln (175) - 0.52

Apply log rules

t = \frac{17 5 ^{0.98}}{e ^{0.52}}

ln^{2} (x - 6) + ln^{2} (m + 1) = 3

lo g_{10} (x \cdot 1 0^{- 3}) = 2.85

x (1 - ln (x)) = 0

lo g_{2} (x) = 3.6 \cdot 1 0^{13}

5 = \frac{1}{3} lo g_{10} (x) + 3

What is the answer to ln(t)=0.98ln(175)-0.52 ?
The answer to ln(t)=0.98ln(175)-0.52 is t=(175^{0.98})/(e^{0.52)}
Solve for t: ln(t)=0.98ln(175)-0.52
The solution is t=(175^{0.98})/(e^{0.52)}