What is the answer to 2log_{4}(x)-log_{4}(x+3)=1 ?

The answer to 2log_{4}(x)-log_{4}(x+3)=1 is x=6

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2log_{4}(x)-log_{4}(x+3)=1

2 lo g_{4} (x) - lo g_{4} (x + 3) = 1

x = 6

Solution steps

2 lo g_{4} (x) - lo g_{4} (x + 3) = 1

Apply log rules

x^{2} = 4 (x + 3)

Solve

x^{2} = 4 (x + 3) : x = 6, x = - 2

x = 6, x = - 2

Verify Solutions:

x = 6

True

, x = - 2

False

The solution is

x = 6

ln (x^{2}) + ln (x) = 2

- ln (1 - x) = 0

lo g_{2} (c) = 4 + lo g_{2} (c - 3)

lo g_{0.5} (x) = 5

lo g_{2} (x + 22) = 3

What is the answer to 2log_{4}(x)-log_{4}(x+3)=1 ?
The answer to 2log_{4}(x)-log_{4}(x+3)=1 is x=6
Solve for x: 2log_{4}(x)-log_{4}(x+3)=1
The solution is x=6