What is the answer to solvefor x,ln(x^2)-1=3 ?

The answer to solvefor x,ln(x^2)-1=3 is x=e^2,x=-e^2

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solvefor x,ln(x^2)-1=3

solve for

x, ln (x^{2}) - 1 = 3

x = e^{2}, x = - e^{2}

Decimal Notation

x = 7.38905 \dots, x = - 7.38905 \dots

Solution steps

ln (x^{2}) - 1 = 3

Move

1

to the right side

ln (x^{2}) = 4

Apply log rules

x^{2} = e^{4}

Solve

x^{2} = e^{4} : x = e^{2}, x = - e^{2}

x = e^{2}, x = - e^{2}

Verify Solutions:

x = e^{2}

True

, x = - e^{2}

True

The solutions are

x = e^{2}, x = - e^{2}

ln (e x) = 1

1.25 ln (x) = e - x 1.72

lo g_{2} (b) = 2

n, lo g_{2} (n) = 1 0^{6}

lo g_{a} (16) = 4

What is the answer to solvefor x,ln(x^2)-1=3 ?
The answer to solvefor x,ln(x^2)-1=3 is x=e^2,x=-e^2