What is the answer to 1-log_{2}(1-x^2)=2 ?

The answer to 1-log_{2}(1-x^2)=2 is x= 1/(sqrt(2)),x=-1/(sqrt(2))

Solve for x: 1-log_{2}(1-x^2)=2

The solution is x= 1/(sqrt(2)),x=-1/(sqrt(2))

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1 - lo g_{2} (1 - x^{2}) = 2

x = \frac{1}{2}, x = - \frac{1}{2}

Decimal Notation

x = 0.70710 \dots, x = - 0.70710 \dots

Solution steps

1 - lo g_{2} (1 - x^{2}) = 2

Move

1

to the right side

- lo g_{2} (1 - x^{2}) = 1

Divide both sides by

- 1

lo g_{2} (1 - x^{2}) = - 1

Apply log rules

1 - x^{2} = \frac{1}{2}

Solve

1 - x^{2} = \frac{1}{2} : x = \frac{1}{2}, x = - \frac{1}{2}

x = \frac{1}{2}, x = - \frac{1}{2}

Verify Solutions:

x = \frac{1}{2}

True

, x = - \frac{1}{2}

True

The solutions are

x = \frac{1}{2}, x = - \frac{1}{2}

4 + ln (27 x) = 22 - 2 ln (x)

lo g_{2} (lo g_{4} (x)) = - 1

ln (1 - 4 x) = - 5.6 x

ln (7 - x) + ln (3 x + 5) = ln (24 x)

- lo g_{10} (x) = 4.19

What is the answer to 1-log_{2}(1-x^2)=2 ?
The answer to 1-log_{2}(1-x^2)=2 is x= 1/(sqrt(2)),x=-1/(sqrt(2))
Solve for x: 1-log_{2}(1-x^2)=2
The solution is x= 1/(sqrt(2)),x=-1/(sqrt(2))