What is the answer to log_{2}(x-1)=4-log_{2}(3) ?

The answer to log_{2}(x-1)=4-log_{2}(3) is x= 19/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2}(x-1)=4-log_{2}(3)

lo g_{2} (x - 1) = 4 - lo g_{2} (3)

x = \frac{19}{3}

Decimal Notation

x = 6.33333 \dots

Solution steps

lo g_{2} (x - 1) = 4 - lo g_{2} (3)

Apply log rules

x - 1 = \frac{16}{3}

Solve

x - 1 = \frac{16}{3} : x = \frac{19}{3}

x = \frac{19}{3}

ln (5 - x) = ln (5) - ln (x)

a, lo g_{b} (a) = c

a, lo g_{b} (a) = 1

∣ ln (x) ∣ = 1

- 5 lo g_{7} (10 n) = 5

What is the answer to log_{2}(x-1)=4-log_{2}(3) ?
The answer to log_{2}(x-1)=4-log_{2}(3) is x= 19/3
Solve for x: log_{2}(x-1)=4-log_{2}(3)
The solution is x= 19/3