What is the answer to solvefor x,y=log_{y}(x)+2 ?

The answer to solvefor x,y=log_{y}(x)+2 is x=y^{y-2} {y>0}

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solvefor x,y=log_{y}(x)+2

solve for

x, y = lo g_{y} (x) + 2

x = y^{y - 2} {y > 0}

Solution steps

y = lo g_{y} (x) + 2

Switch sides

lo g_{y} (x) + 2 = y

Move

2

to the right side

lo g_{y} (x) = y - 2

Apply log rules

x = y^{y - 2}

Verify Solutions:

x = y^{y - 2} {y > 0}

The solution is

x = y^{y - 2} {y > 0}

ln (\frac{x}{2}) = 6.78

ln (5 x - 7) - ln (x + 1) = ln (3)

2 + 3 ln (4 x - 3) = 20

lo g_{5} (x + 4) = 2

4 - ln (x + 1) = ln (x + 1)

What is the answer to solvefor x,y=log_{y}(x)+2 ?
The answer to solvefor x,y=log_{y}(x)+2 is x=y^{y-2} {y>0}