What is the answer to log_{10}(x-1)+log_{10}(5x)=2 ?

The answer to log_{10}(x-1)+log_{10}(5x)=2 is x=5

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log_{10}(x-1)+log_{10}(5x)=2

lo g_{10} (x - 1) + lo g_{10} (5 x) = 2

x = 5

Solution steps

lo g_{10} (x - 1) + lo g_{10} (5 x) = 2

Apply log rules

(x - 1) \cdot 5 x = 100

Solve

(x - 1) \cdot 5 x = 100 : x = 5, x = - 4

x = 5, x = - 4

Verify Solutions:

x = 5

True

, x = - 4

False

The solution is

x = 5

50 = 0.5 x + 2 ln (x)

lo g_{6} (- 3 x) + lo g_{6} (- 10 x) = 5

5 + ln (x - 5) = 2

x, 3 x + y + ln (x y) = C

x, ln (x) = 2 t + 4

What is the answer to log_{10}(x-1)+log_{10}(5x)=2 ?
The answer to log_{10}(x-1)+log_{10}(5x)=2 is x=5
Solve for x: log_{10}(x-1)+log_{10}(5x)=2
The solution is x=5