What are the solutions to the equation 3.1x^2-5.2x+1.7=0 ?

The solutions to the equation 3.1x^2-5.2x+1.7=0 are x=(26+sqrt(149))/(31),x=(26-sqrt(149))/(31)

Find the zeros of 3.1x^2-5.2x+1.7=0

The zeros of 3.1x^2-5.2x+1.7=0 are x=(26+sqrt(149))/(31),x=(26-sqrt(149))/(31)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3.1 x^{2} - 5.2 x + 1.7 = 0

x = \frac{26 + 149}{31}, x = \frac{26 - 149}{31}

Solution steps

3.1 x^{2} - 5.2 x + 1.7 = 0

Multiply both sides by

10

31 x^{2} - 52 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 52 ) \pm ( - 52 ) ^{2} - 4 \cdot 31 \cdot 17}{2 \cdot 31}

(- 52)^{2} - 4 \cdot 31 \cdot 17 = 2149

x_{1, 2} = \frac{- ( - 52 ) \pm 2 149}{2 \cdot 31}

Separate the solutions

x_{1} = \frac{- ( - 52 ) + 2 149}{2 \cdot 31}, x_{2} = \frac{- ( - 52 ) - 2 149}{2 \cdot 31}

x = \frac{- ( - 52 ) + 2 149}{2 \cdot 31} : \frac{26 + 149}{31}

x = \frac{- ( - 52 ) - 2 149}{2 \cdot 31} : \frac{26 - 149}{31}

The solutions to the quadratic equation are:

x = \frac{26 + 149}{31}, x = \frac{26 - 149}{31}

4 x - 7 \leq - 32 + 9 x

10 - 2 u = 2

2 x^{2} - x - 28 = 0

∣ 16 x + 20 ∣ = 8

e^{l n (5)}

What are the solutions to the equation 3.1x^2-5.2x+1.7=0 ?
The solutions to the equation 3.1x^2-5.2x+1.7=0 are x=(26+sqrt(149))/(31),x=(26-sqrt(149))/(31)
Find the zeros of 3.1x^2-5.2x+1.7=0
The zeros of 3.1x^2-5.2x+1.7=0 are x=(26+sqrt(149))/(31),x=(26-sqrt(149))/(31)