What is the answer to log_{2}(x)=log_{2}(3x-1) ?

The answer to log_{2}(x)=log_{2}(3x-1) is x= 1/2

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log_{2}(x)=log_{2}(3x-1)

lo g_{2} (x) = lo g_{2} (3 x - 1)

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

lo g_{2} (x) = lo g_{2} (3 x - 1)

Apply log rules

x = 3 x - 1

Solve

x = 3 x - 1 : x = \frac{1}{2}

x = \frac{1}{2}

Verify Solutions:

x = \frac{1}{2}

True

The solution is

x = \frac{1}{2}

lo g_{5} (x + 2) - lo g_{5} (x - 2) = 3

5 ln (8 x - 5) - 20 = 5

lo g_{10} (3 x - 1) = 2

x^{2} ln (x) - \frac{x ^{2}}{2} = 0

x, lo g_{x} (y) = 5

What is the answer to log_{2}(x)=log_{2}(3x-1) ?
The answer to log_{2}(x)=log_{2}(3x-1) is x= 1/2
Solve for x: log_{2}(x)=log_{2}(3x-1)
The solution is x= 1/2