What is the answer to log_{10}(3)+log_{10}(x-7)=1 ?

The answer to log_{10}(3)+log_{10}(x-7)=1 is x= 31/3

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log_{10}(3)+log_{10}(x-7)=1

lo g_{10} (3) + lo g_{10} (x - 7) = 1

x = \frac{31}{3}

Decimal Notation

x = 10.33333 \dots

Solution steps

lo g_{10} (3) + lo g_{10} (x - 7) = 1

Move

lo g_{10} (3)

to the right side

lo g_{10} (x - 7) = 1 - lo g_{10} (3)

Apply log rules

x - 7 = \frac{10}{3}

Solve

x - 7 = \frac{10}{3} : x = \frac{31}{3}

x = \frac{31}{3}

Verify Solutions:

x = \frac{31}{3}

True

The solution is

x = \frac{31}{3}

lo g_{10} (x) = 1.5306

x, Z = x y + ln (x + y)

61 = lo g_{10} (\frac{100}{x})

ln (x) = 4.123

lo g_{x} (\frac{27}{64}) = - 3

What is the answer to log_{10}(3)+log_{10}(x-7)=1 ?
The answer to log_{10}(3)+log_{10}(x-7)=1 is x= 31/3
Solve for x: log_{10}(3)+log_{10}(x-7)=1
The solution is x= 31/3