What is the answer to log_{3}(3x+8)+log_{3}(x)=1 ?

The answer to log_{3}(3x+8)+log_{3}(x)=1 is x= 1/3

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log_{3}(3x+8)+log_{3}(x)=1

lo g_{3} (3 x + 8) + lo g_{3} (x) = 1

x = \frac{1}{3}

Decimal Notation

x = 0.33333 \dots

Solution steps

lo g_{3} (3 x + 8) + lo g_{3} (x) = 1

Apply log rules

(3 x + 8) x = 3

Solve

(3 x + 8) x = 3 : x = \frac{1}{3}, x = - 3

x = \frac{1}{3}, x = - 3

Verify Solutions:

x = \frac{1}{3}

True

, x = - 3

False

The solution is

x = \frac{1}{3}

ln (P) = ln (50000) + 0.075 (5)

6.52 = - lo g_{10} (x)

lo g_{2} (4 x - 2) = 5

9 ln (x + 7) = 18

lo g_{10} (y) = lo g_{10} (8)

What is the answer to log_{3}(3x+8)+log_{3}(x)=1 ?
The answer to log_{3}(3x+8)+log_{3}(x)=1 is x= 1/3
Solve for x: log_{3}(3x+8)+log_{3}(x)=1
The solution is x= 1/3