What is the answer to ln(5)=1+ln(2x) ?

The answer to ln(5)=1+ln(2x) is x= 5/(2e)

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ln(5)=1+ln(2x)

ln (5) = 1 + ln (2 x)

x = \frac{5}{2 e}

Decimal Notation

x = 0.91969 \dots

Solution steps

ln (5) = 1 + ln (2 x)

Switch sides

1 + ln (2 x) = ln (5)

Move

1

to the right side

ln (2 x) = ln (5) - 1

Apply log rules

2 x = \frac{5}{e}

Solve

2 x = \frac{5}{e} : x = \frac{5}{2 e}

x = \frac{5}{2 e}

Verify Solutions:

x = \frac{5}{2 e}

True

The solution is

x = \frac{5}{2 e}

2 ln (x - 1) - ln (x) = 1

x, lo g_{e} (2 x - 1) = - 3

lo g_{2} (- 5 x + 8) = 1

1.5 n^{2} - 7.5 n lo g_{10} (n) = 0

6 ln (5 x - 3) + 12 = 0

What is the answer to ln(5)=1+ln(2x) ?
The answer to ln(5)=1+ln(2x) is x= 5/(2e)
Solve for x: ln(5)=1+ln(2x)
The solution is x= 5/(2e)