What is the answer to log_{6}(x-4)+log_{6}(x-5)=1 ?

The answer to log_{6}(x-4)+log_{6}(x-5)=1 is x=7

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log_{6}(x-4)+log_{6}(x-5)=1

lo g_{6} (x - 4) + lo g_{6} (x - 5) = 1

x = 7

Solution steps

lo g_{6} (x - 4) + lo g_{6} (x - 5) = 1

Apply log rules

(x - 4) (x - 5) = 6

Solve

(x - 4) (x - 5) = 6 : x = 7, x = 2

x = 7, x = 2

Verify Solutions:

x = 7

True

, x = 2

False

The solution is

x = 7

lo g_{10} (x) (x^{2}) = x^{3}

x^{2 l o g_{x} (x + 1)} = 5 x - 1

lo g_{3} (x - x - 5) - lo g_{3} (x) = 1

ln (2 x - 3) = 0

ln (2 x - 3) = 4

What is the answer to log_{6}(x-4)+log_{6}(x-5)=1 ?
The answer to log_{6}(x-4)+log_{6}(x-5)=1 is x=7
Solve for x: log_{6}(x-4)+log_{6}(x-5)=1
The solution is x=7