What is the answer to 5=log_{4}(x)+log_{4}(x)+1 ?

The answer to 5=log_{4}(x)+log_{4}(x)+1 is x=16

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5=log_{4}(x)+log_{4}(x)+1

5 = lo g_{4} (x) + lo g_{4} (x) + 1

x = 16

Solution steps

5 = lo g_{4} (x) + lo g_{4} (x) + 1

Switch sides

lo g_{4} (x) + lo g_{4} (x) + 1 = 5

Add similar elements:

lo g_{4} (x) + lo g_{4} (x) = 2 lo g_{4} (x)

2 lo g_{4} (x) + 1 = 5

Move

1

to the right side

2 lo g_{4} (x) = 4

Divide both sides by

2

lo g_{4} (x) = 2

Apply log rules

x = 16

Verify Solutions:

x = 16

True

The solution is

x = 16

lo g_{2} (2 x + 3) - lo g_{2} (x) = 3

lo g_{a} (- x) - lo g_{a} (2 - x) = 2

ln (x) = 5.77

ln (x - 8) = ln (x^{3} + x)

ln (1 - 2 x) = ln (5)

What is the answer to 5=log_{4}(x)+log_{4}(x)+1 ?
The answer to 5=log_{4}(x)+log_{4}(x)+1 is x=16
Solve for x: 5=log_{4}(x)+log_{4}(x)+1
The solution is x=16