What is the answer to log_{3}(x)+log_{3}(x+1)=8 ?

The answer to log_{3}(x)+log_{3}(x+1)=8 is x=(-1+sqrt(26245))/2

Solve for x: log_{3}(x)+log_{3}(x+1)=8

The solution is x=(-1+sqrt(26245))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

lo g_{3} (x) + lo g_{3} (x + 1) = 8

x = \frac{- 1 + 26245}{2}

Decimal Notation

x = 80.50154 \dots

Solution steps

lo g_{3} (x) + lo g_{3} (x + 1) = 8

Apply log rules

x (x + 1) = 6561

Solve

x (x + 1) = 6561 : x = \frac{- 1 + 26245}{2}, x = \frac{- 1 - 26245}{2}

x = \frac{- 1 + 26245}{2}, x = \frac{- 1 - 26245}{2}

Verify Solutions:

x = \frac{- 1 + 26245}{2}

True

, x = \frac{- 1 - 26245}{2}

False

The solution is

x = \frac{- 1 + 26245}{2}

0.1 = lo g_{10} (x)

T, - lo g_{10} (T) = 6.016

lo g_{2} (2 x) = 2

3 lo g_{2} (x) - 2 lo g_{3} (x) = 1

lo g_{3} (- 2 x) + lo g_{3} (12) = 3

What is the answer to log_{3}(x)+log_{3}(x+1)=8 ?
The answer to log_{3}(x)+log_{3}(x+1)=8 is x=(-1+sqrt(26245))/2
Solve for x: log_{3}(x)+log_{3}(x+1)=8
The solution is x=(-1+sqrt(26245))/2