What is the answer to 2log_{3}(y-2)-log_{3}(y-4)=2 ?

The answer to 2log_{3}(y-2)-log_{3}(y-4)=2 is y=8,y=5

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2log_{3}(y-2)-log_{3}(y-4)=2

2 lo g_{3} (y - 2) - lo g_{3} (y - 4) = 2

y = 8, y = 5

Solution steps

2 lo g_{3} (y - 2) - lo g_{3} (y - 4) = 2

Apply log rules

(y - 2)^{2} = 9 (y - 4)

Solve

(y - 2)^{2} = 9 (y - 4) : y = 8, y = 5

y = 8, y = 5

Verify Solutions:

y = 8

True

, y = 5

True

The solutions are

y = 8, y = 5

lo g_{16} (x) = - \frac{1}{2}

- 5 = lo g_{10} (x)

ln (x + 1) + ln (x - 1) = 1

ln (x + 1) + ln (x - 1) = 0

lo g_{4} (x) = (lo g_{4} (x))^{4}

What is the answer to 2log_{3}(y-2)-log_{3}(y-4)=2 ?
The answer to 2log_{3}(y-2)-log_{3}(y-4)=2 is y=8,y=5
Solve for y: 2log_{3}(y-2)-log_{3}(y-4)=2
The solution is y=8,y=5