What is the answer to log_{3}(6x)+log_{3}(2)=3 ?

The answer to log_{3}(6x)+log_{3}(2)=3 is x= 9/4

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log_{3}(6x)+log_{3}(2)=3

lo g_{3} (6 x) + lo g_{3} (2) = 3

x = \frac{9}{4}

Decimal Notation

x = 2.25

Solution steps

lo g_{3} (6 x) + lo g_{3} (2) = 3

Move

lo g_{3} (2)

to the right side

lo g_{3} (6 x) = 3 - lo g_{3} (2)

Apply log rules

6 x = \frac{27}{2}

Solve

6 x = \frac{27}{2} : x = \frac{9}{4}

x = \frac{9}{4}

Verify Solutions:

x = \frac{9}{4}

True

The solution is

x = \frac{9}{4}

x, ln (y) = - 3 ln (x) + c

lo g_{3} (4 x + 10) = lo g_{3} (x + 1)

\frac{ln ( 2 x - 5 )}{2} = 6

ln (t) - 66125 = - 0.07 t

lo g_{10} (x) - lo g_{10} (x + 7) = 1

What is the answer to log_{3}(6x)+log_{3}(2)=3 ?
The answer to log_{3}(6x)+log_{3}(2)=3 is x= 9/4
Solve for x: log_{3}(6x)+log_{3}(2)=3
The solution is x= 9/4