What is the answer to ln(x+1)+x/(x+1)=0 ?

The answer to ln(x+1)+x/(x+1)=0 is x=0

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ln(x+1)+x/(x+1)=0

ln (x + 1) + \frac{x}{x + 1} = 0

x = 0

Solution steps

ln (x + 1) + \frac{x}{x + 1} = 0

Move

\frac{x}{x + 1}

to the right side

ln (x + 1) = - \frac{x}{x + 1}

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{l n (x + 1)} = e^{- \frac{x}{x + 1}}

Simplify

e^{l n (x + 1)} : x + 1

x + 1 = e^{- \frac{x}{x + 1}}

Solve

x + 1 = e^{- \frac{x}{x + 1}} : x = 0

x = 0

Verify Solutions:

x = 0

True

The solution is

x = 0

9.24 = lo g_{1} (x)

lo g_{x} (2 x + 15) = 2

ln (x) = 3.967503513

lo g_{10} (5 x) - lo g_{10} (x - 1) = 2

3 lo g_{8} (2) = lo g_{8} (x)

What is the answer to ln(x+1)+x/(x+1)=0 ?
The answer to ln(x+1)+x/(x+1)=0 is x=0
Solve for x: ln(x+1)+x/(x+1)=0
The solution is x=0