What is the answer to log_{2}(5x)+4log_{2}(3)=5 ?

The answer to log_{2}(5x)+4log_{2}(3)=5 is x= 32/405

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2}(5x)+4log_{2}(3)=5

lo g_{2} (5 x) + 4 lo g_{2} (3) = 5

x = \frac{32}{405}

Decimal Notation

x = 0.07901 \dots

Solution steps

lo g_{2} (5 x) + 4 lo g_{2} (3) = 5

Move

4 lo g_{2} (3)

to the right side

lo g_{2} (5 x) = 5 - 4 lo g_{2} (3)

Apply log rules

5 x = \frac{32}{81}

Solve

5 x = \frac{32}{81} : x = \frac{32}{405}

x = \frac{32}{405}

Verify Solutions:

x = \frac{32}{405}

True

The solution is

x = \frac{32}{405}

lo g_{10} (\frac{x}{0.5}) = 0.25

lo g_{3} (z) = 3

x^{5 - l o g_{3} (x)} = 9 x^{2}

\frac{1}{ln ( x )} = 0

lo g_{3} (x - 1) = 4

What is the answer to log_{2}(5x)+4log_{2}(3)=5 ?
The answer to log_{2}(5x)+4log_{2}(3)=5 is x= 32/405
Solve for x: log_{2}(5x)+4log_{2}(3)=5
The solution is x= 32/405