What is the answer to log_{2}((r+9)^2)=6 ?

The answer to log_{2}((r+9)^2)=6 is r=-1,r=-17

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log_{2}((r+9)^2)=6

lo g_{2} ((r + 9)^{2}) = 6

r = - 1, r = - 17

Solution steps

lo g_{2} ((r + 9)^{2}) = 6

Apply log rules

(r + 9)^{2} = 64

Solve

(r + 9)^{2} = 64 : r = - 1, r = - 17

r = - 1, r = - 17

lo g_{3} (10 - x) - lo g_{3} (x + 2) = 1

lo g_{10} (y^{10}) = 2

2 lo g_{10} (x) + 1 = 5

2 lo g_{2} (x) = 4

(ln (x))^{2} = 10 - 9 ln (x)

What is the answer to log_{2}((r+9)^2)=6 ?
The answer to log_{2}((r+9)^2)=6 is r=-1,r=-17
Solve for r: log_{2}((r+9)^2)=6
The solution is r=-1,r=-17