What is the answer to ln(7)+ln(x+3)=log_{e}(2x+6) ?

The answer to ln(7)+ln(x+3)=log_{e}(2x+6) is No Solution for x\in\mathbb{R}

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ln(7)+ln(x+3)=log_{e}(2x+6)

ln (7) + ln (x + 3) = lo g_{e} (2 x + 6)

No Solution for x \in R

Solution steps

ln (7) + ln (x + 3) = lo g_{e} (2 x + 6)

Apply log rules

7 (x + 3) = 2 x + 6

Solve

7 (x + 3) = 2 x + 6 : x = - 3

x = - 3

Verify Solutions:

x = - 3

False

The solution is

No Solution for x \in R

lo g_{a} (3) = 7

x, f^{- 1} (x) = ln (x + 3)

8 + ln (8 x) = 26 - 2 ln (x)

3 = 8 lo g_{10} (6 x + 3)

0 = 2 x ln (2 x) + x

What is the answer to ln(7)+ln(x+3)=log_{e}(2x+6) ?
The answer to ln(7)+ln(x+3)=log_{e}(2x+6) is No Solution for x\in\mathbb{R}