What is the answer to log_{3}(x-1)+log_{3}(x+1)=1 ?

The answer to log_{3}(x-1)+log_{3}(x+1)=1 is x=2

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log_{3}(x-1)+log_{3}(x+1)=1

lo g_{3} (x - 1) + lo g_{3} (x + 1) = 1

x = 2

Solution steps

lo g_{3} (x - 1) + lo g_{3} (x + 1) = 1

Apply log rules

(x - 1) (x + 1) = 3

Solve

(x - 1) (x + 1) = 3 : x = 2, x = - 2

x = 2, x = - 2

Verify Solutions:

x = 2

True

, x = - 2

False

The solution is

x = 2

- 10 = 20 lo g_{10} (x)

lo g_{36} (6^{a}) = a + 1

ln (8 x) - ln (x - 3) = ln (x + 3)

ln (10 + x) = ln (3 + 4 x)

2 ln (7 x - 2) - 19 = - 3

What is the answer to log_{3}(x-1)+log_{3}(x+1)=1 ?
The answer to log_{3}(x-1)+log_{3}(x+1)=1 is x=2
Solve for x: log_{3}(x-1)+log_{3}(x+1)=1
The solution is x=2