What is the answer to log_{16}(x)=(log_{4}(x^2)) ?

The answer to log_{16}(x)=(log_{4}(x^2)) is x=1

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log_{16}(x)=(log_{4}(x^2))

lo g_{16} (x) = (lo g_{4} (x^{2}))

x = 1

Solution steps

lo g_{16} (x) = (lo g_{4} (x^{2}))

Apply log rules

x = 1

Verify Solutions:

x = 1

True

The solution is

x = 1

20 \cdot lo g_{10} (x) = - 3

lo g_{10} (x) = 3.58

- \frac{( ln ( x ) )}{x ^{2}} = 0

lo g_{10} (x) = 3.04

x, ln (3) = - ln (x)

What is the answer to log_{16}(x)=(log_{4}(x^2)) ?
The answer to log_{16}(x)=(log_{4}(x^2)) is x=1
Solve for x: log_{16}(x)=(log_{4}(x^2))
The solution is x=1