What is the answer to 2+log_{3}(x-1)=log_{3}(x),x ?

The answer to 2+log_{3}(x-1)=log_{3}(x),x is x= 9/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2+log_{3}(x-1)=log_{3}(x),x

2 + lo g_{3} (x - 1) = lo g_{3} (x), x

x = \frac{9}{8}

Decimal Notation

x = 1.125

Solution steps

2 + lo g_{3} (x - 1) = lo g_{3} (x)

Apply log rules

9 (x - 1) = x

Solve

9 (x - 1) = x : x = \frac{9}{8}

x = \frac{9}{8}

Verify Solutions:

x = \frac{9}{8}

True

The solution is

x = \frac{9}{8}

lo g_{10} (x) = 4.78

lo g_{x} (16) = \frac{1}{2}

ln (x) = 8.077133955

ln (x^{2}) = ln^{2} (x)

lo g_{x} (3^{x}) = \frac{x}{2}

What is the answer to 2+log_{3}(x-1)=log_{3}(x),x ?
The answer to 2+log_{3}(x-1)=log_{3}(x),x is x= 9/8
Solve for x: 2+log_{3}(x-1)=log_{3}(x),x
The solution is x= 9/8