What is the answer to log_{x+1}(4)=2 ?

The answer to log_{x+1}(4)=2 is x=1

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log_{x+1}(4)=2

lo g_{x + 1} (4) = 2

x = 1

Solution steps

lo g_{x + 1} (4) = 2

Apply log rules

\frac{1}{lo g _{4} ( x + 1 )} = 2

Multiply both sides by

lo g_{4} (x + 1)

\frac{1}{lo g _{4} ( x + 1 )} lo g_{4} (x + 1) = 2 lo g_{4} (x + 1)

Simplify

1 = 2 lo g_{4} (x + 1)

Switch sides

2 lo g_{4} (x + 1) = 1

Divide both sides by

2

lo g_{4} (x + 1) = \frac{1}{2}

Apply log rules

x + 1 = 2

Solve

x + 1 = 2 : x = 1

x = 1

Verify Solutions:

x = 1

True

The solution is

x = 1

0.23 = ln (y)

lo g_{10} (- x - 4) = 2

50 = - 23.98 ln (x) + 33.243

2 ln (x - 6) = - 2

ln (x + 6) - ln (x - 4) = ln (x)