What are the solutions to the equation 2x^2-4x+5=0 ?

The solutions to the equation 2x^2-4x+5=0 are x=1+isqrt(3/2),x=1-isqrt(3/2)

Find the zeros of 2x^2-4x+5=0

The zeros of 2x^2-4x+5=0 are x=1+isqrt(3/2),x=1-isqrt(3/2)

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2 x^{2} - 4 x + 5 = 0

x = 1 + i \frac{3}{2}, x = 1 - i \frac{3}{2}

Solution steps

2 x^{2} - 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 \cdot 5}{2 \cdot 2}

Simplify

(- 4)^{2} - 4 \cdot 2 \cdot 5 : 26 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 6 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 6 i}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 2 6 i}{2 \cdot 2}

x = \frac{- ( - 4 ) + 2 6 i}{2 \cdot 2} : 1 + i \frac{3}{2}

x = \frac{- ( - 4 ) - 2 6 i}{2 \cdot 2} : 1 - i \frac{3}{2}

The solutions to the quadratic equation are:

x = 1 + i \frac{3}{2}, x = 1 - i \frac{3}{2}

6 g^{3} + 18 g^{2} + 5 g + 15

1.3 \cdot 2

2 ∣ 25 x ∣ + 50 = 100

143 \cdot 2

w^{2} = 9 (w - 6)

What are the solutions to the equation 2x^2-4x+5=0 ?
The solutions to the equation 2x^2-4x+5=0 are x=1+isqrt(3/2),x=1-isqrt(3/2)
Find the zeros of 2x^2-4x+5=0
The zeros of 2x^2-4x+5=0 are x=1+isqrt(3/2),x=1-isqrt(3/2)