What is the answer to log_{2}(9x)+2log_{2}(8)=3 ?

The answer to log_{2}(9x)+2log_{2}(8)=3 is x= 1/72

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log_{2}(9x)+2log_{2}(8)=3

lo g_{2} (9 x) + 2 lo g_{2} (8) = 3

x = \frac{1}{72}

Decimal Notation

x = 0.01388 \dots

Solution steps

lo g_{2} (9 x) + 2 lo g_{2} (8) = 3

Move

2 lo g_{2} (8)

to the right side

lo g_{2} (9 x) = 3 - 2 lo g_{2} (8)

Apply log rules

9 x = \frac{1}{8}

Solve

9 x = \frac{1}{8} : x = \frac{1}{72}

x = \frac{1}{72}

Verify Solutions:

x = \frac{1}{72}

True

The solution is

x = \frac{1}{72}

lo g_{4} (x - 3) = - lo g_{4} (x - 6) + 1

ln (3 x - 15) = 6

lo g_{3} (x + 2) - lo g_{3} (x) = 2

lo g_{x} (6) = \frac{1}{3}

ln (3 x - 15) = 5

What is the answer to log_{2}(9x)+2log_{2}(8)=3 ?
The answer to log_{2}(9x)+2log_{2}(8)=3 is x= 1/72
Solve for x: log_{2}(9x)+2log_{2}(8)=3
The solution is x= 1/72