What is the answer to 1+log_{6}(x)=log_{6}(2x+4) ?

The answer to 1+log_{6}(x)=log_{6}(2x+4) is x=1

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1+log_{6}(x)=log_{6}(2x+4)

1 + lo g_{6} (x) = lo g_{6} (2 x + 4)

x = 1

Solution steps

1 + lo g_{6} (x) = lo g_{6} (2 x + 4)

Apply log rules

6 x = 2 x + 4

Solve

6 x = 2 x + 4 : x = 1

x = 1

Verify Solutions:

x = 1

True

The solution is

x = 1

x, lo g_{2} (x) = 4

6.01 - 9.69 = lo g_{10} (x)

lo g_{4} (2 + x) - lo g_{4} (3 - 5 x) = 3

lo g_{4} (x) + 6 lo g_{x} (4) - 5 = 0

7.4 = 6.1 + lo g_{10} (x)

What is the answer to 1+log_{6}(x)=log_{6}(2x+4) ?
The answer to 1+log_{6}(x)=log_{6}(2x+4) is x=1
Solve for x: 1+log_{6}(x)=log_{6}(2x+4)
The solution is x=1