What is the answer to 1+log_{2}(x-2)=log_{2}(x) ?

The answer to 1+log_{2}(x-2)=log_{2}(x) is x=4

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1+log_{2}(x-2)=log_{2}(x)

1 + lo g_{2} (x - 2) = lo g_{2} (x)

x = 4

Solution steps

1 + lo g_{2} (x - 2) = lo g_{2} (x)

Apply log rules

2 (x - 2) = x

Solve

2 (x - 2) = x : x = 4

x = 4

Verify Solutions:

x = 4

True

The solution is

x = 4

ln (x) + ln (x^{3}) = 0

ln (x - 6) + ln (x) = ln (x - 30)

lo g_{8} (x) = 1

ln (6) - ln (5 x + 2) = 8

lo g_{3} (4) - lo g_{3} (x) = 2

What is the answer to 1+log_{2}(x-2)=log_{2}(x) ?
The answer to 1+log_{2}(x-2)=log_{2}(x) is x=4
Solve for x: 1+log_{2}(x-2)=log_{2}(x)
The solution is x=4