What is the answer to 2ln(x+3)-ln(x)=ln(x+3a) ?

The answer to 2ln(x+3)-ln(x)=ln(x+3a) is x=-3/(-a+2) {a>2}

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2ln(x+3)-ln(x)=ln(x+3a)

2 ln (x + 3) - ln (x) = ln (x + 3 a)

x = - \frac{3}{- a + 2} {a > 2}

Solution steps

2 ln (x + 3) - ln (x) = ln (x + 3 a)

Apply log rules

(x + 3)^{2} = (x + 3 a) x

Solve

(x + 3)^{2} = (x + 3 a) x : x = - \frac{3}{- a + 2}

x = - \frac{3}{- a + 2}

Verify Solutions:

x = - \frac{3}{- a + 2} {a > 2}

The solution is

x = - \frac{3}{- a + 2} {a > 2}

y, ln (y) = - 6 x^{2}

lo g_{4} (5 x + 4) - lo g_{4} (4 - x) = 1

50 = 1200 \cdot lo g_{2} (x)

0.48 = lo g_{x} (x)

y, ln (y) = 3 ln (x)

What is the answer to 2ln(x+3)-ln(x)=ln(x+3a) ?
The answer to 2ln(x+3)-ln(x)=ln(x+3a) is x=-3/(-a+2) {a>2}