What is the answer to log_{2}(x^2+3x-2)=1 ?

The answer to log_{2}(x^2+3x-2)=1 is x=1,x=-4

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log_{2}(x^2+3x-2)=1

lo g_{2} (x^{2} + 3 x - 2) = 1

x = 1, x = - 4

Solution steps

lo g_{2} (x^{2} + 3 x - 2) = 1

Apply log rules

x^{2} + 3 x - 2 = 2

Solve

x^{2} + 3 x - 2 = 2 : x = 1, x = - 4

x = 1, x = - 4

lo g_{x} (x) + lo g_{10} (8) = 2

6 + ln (x) = 8

y, x = \frac{ln ( 5 y )}{5}

- 0.688 = lo g_{10} (x)

x, ln (3 x) = 0

What is the answer to log_{2}(x^2+3x-2)=1 ?
The answer to log_{2}(x^2+3x-2)=1 is x=1,x=-4
Solve for x: log_{2}(x^2+3x-2)=1
The solution is x=1,x=-4