What is the answer to log_{9}(x)-log_{3}(x)=2 ?

The answer to log_{9}(x)-log_{3}(x)=2 is x= 1/81

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log_{9}(x)-log_{3}(x)=2

lo g_{9} (x) - lo g_{3} (x) = 2

x = \frac{1}{81}

Decimal Notation

x = 0.01234 \dots

Solution steps

lo g_{9} (x) - lo g_{3} (x) = 2

Apply log rules

x = \frac{1}{81}

Verify Solutions:

x = \frac{1}{81}

True

The solution is

x = \frac{1}{81}

ln (x) + ln (9) = ln (18)

lo g_{27} (2 x - 1) = \frac{4}{3}

lo g_{2} (x) = lo g_{x} (2) + 2

lo g_{10} (x - 5) = 17

lo g_{\frac{1}{2}} (x + 3) = - 2

What is the answer to log_{9}(x)-log_{3}(x)=2 ?
The answer to log_{9}(x)-log_{3}(x)=2 is x= 1/81
Solve for x: log_{9}(x)-log_{3}(x)=2
The solution is x= 1/81