What is the answer to log_{2}(6x+3)=5 ?

The answer to log_{2}(6x+3)=5 is x= 29/6

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log_{2}(6x+3)=5

lo g_{2} (6 x + 3) = 5

x = \frac{29}{6}

Solution steps

lo g_{2} (6 x + 3) = 5

Apply log rules

6 x + 3 = 32

Solve

6 x + 3 = 32 : x = \frac{29}{6}

x = \frac{29}{6}

lo g_{5} (x^{4}) + lo g_{5} (x) = 8

lo g_{10} (16) = 2 lo g_{10} (x + 1)

2 lo g_{3} (3 x - 2) = 2

lo g_{x + 5} (2 x^{2} + 1) = 2

3.28 = 11.6 \cdot ln (c)

What is the answer to log_{2}(6x+3)=5 ?
The answer to log_{2}(6x+3)=5 is x= 29/6
Solve for x: log_{2}(6x+3)=5
The solution is x= 29/6