What is the answer to ln(x^2+x)=5 ?

The answer to ln(x^2+x)=5 is x=(-1+sqrt(1+4e^5))/2 ,x=(-1-sqrt(1+4e^5))/2

Solve for x: ln(x^2+x)=5

The solution is x=(-1+sqrt(1+4e^5))/2 ,x=(-1-sqrt(1+4e^5))/2

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ln (x^{2} + x) = 5

x = \frac{- 1 + 1 + 4 e ^{5}}{2}, x = \frac{- 1 - 1 + 4 e ^{5}}{2}

Solution steps

ln (x^{2} + x) = 5

Apply log rules

x^{2} + x = e^{5}

Solve

x^{2} + x = e^{5} : x = \frac{- 1 + 1 + 4 e ^{5}}{2}, x = \frac{- 1 - 1 + 4 e ^{5}}{2}

x = \frac{- 1 + 1 + 4 e ^{5}}{2}, x = \frac{- 1 - 1 + 4 e ^{5}}{2}

lo g_{10} (1 - x) = 0

x, ln (x) = - ln (y)

lo g_{8} (x + 4) - lo g_{8} (x - 3) = 1

lo g_{10} (x) + lo g_{10} (4) = 2

lo g_{8} ((x - 3)^{9}) = 6

What is the answer to ln(x^2+x)=5 ?
The answer to ln(x^2+x)=5 is x=(-1+sqrt(1+4e^5))/2 ,x=(-1-sqrt(1+4e^5))/2
Solve for x: ln(x^2+x)=5
The solution is x=(-1+sqrt(1+4e^5))/2 ,x=(-1-sqrt(1+4e^5))/2