What is the answer to log_{3}(x+4)=1+log_{3}(x-2) ?

The answer to log_{3}(x+4)=1+log_{3}(x-2) is x=5

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log_{3}(x+4)=1+log_{3}(x-2)

lo g_{3} (x + 4) = 1 + lo g_{3} (x - 2)

x = 5

Solution steps

lo g_{3} (x + 4) = 1 + lo g_{3} (x - 2)

Apply log rules

x + 4 = 3 (x - 2)

Solve

x + 4 = 3 (x - 2) : x = 5

x = 5

Verify Solutions:

x = 5

True

The solution is

x = 5

ln (x) = \frac{a}{3 + 1}

3 ln (x + 6) = - 3

ln (x) - ln (3 x - 3) = ln (4)

2 lo g_{10} (x) - lo g_{10} (3 x) = 0

ln (x) = 5.320363224

What is the answer to log_{3}(x+4)=1+log_{3}(x-2) ?
The answer to log_{3}(x+4)=1+log_{3}(x-2) is x=5
Solve for x: log_{3}(x+4)=1+log_{3}(x-2)
The solution is x=5