What is the answer to log_{4}(x-3)+log_{4}(x+9)=3 ?

The answer to log_{4}(x-3)+log_{4}(x+9)=3 is x=7

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log_{4}(x-3)+log_{4}(x+9)=3

lo g_{4} (x - 3) + lo g_{4} (x + 9) = 3

x = 7

Solution steps

lo g_{4} (x - 3) + lo g_{4} (x + 9) = 3

Apply log rules

(x - 3) (x + 9) = 64

Solve

(x - 3) (x + 9) = 64 : x = 7, x = - 13

x = 7, x = - 13

Verify Solutions:

x = 7

True

, x = - 13

False

The solution is

x = 7

x, ln (3 x - 10) = 5

lo g_{4} (3 x + 2) = 3

lo g_{x} (9) = 2

lo g_{2} (5 \cdot x) = 10

ln (b x) = - 1

What is the answer to log_{4}(x-3)+log_{4}(x+9)=3 ?
The answer to log_{4}(x-3)+log_{4}(x+9)=3 is x=7
Solve for x: log_{4}(x-3)+log_{4}(x+9)=3
The solution is x=7