What is the answer to log_{x}(5)=log_{27}(3) ?

The answer to log_{x}(5)=log_{27}(3) is x=125

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log_{x}(5)=log_{27}(3)

lo g_{x} (5) = lo g_{27} (3)

x = 125

Solution steps

lo g_{x} (5) = lo g_{27} (3)

Apply log rules

\frac{1}{lo g _{5} ( x )} = \frac{1}{3}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

1 \cdot 3 = lo g_{5} (x) \cdot 1

Simplify

3 = lo g_{5} (x)

Apply log rules

125 = x

Switch sides

x = 125

Verify Solutions:

x = 125

True

The solution is

x = 125

2 = 2 + ln (x)

ln (x) + ln (25) = ln (x^{3})

lo g_{x} (\frac{243}{32}) = 5

lo g_{7} (x^{2}) = 2 lo g_{7} (x)

ln (- x + 2) = 6

What is the answer to log_{x}(5)=log_{27}(3) ?
The answer to log_{x}(5)=log_{27}(3) is x=125
Solve for x: log_{x}(5)=log_{27}(3)
The solution is x=125